Solve the following system:
{2 x+3 y = 9 | (equation 1)
x+5 y = 8 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x+3 y = 9 | (equation 1)
0 x+(7 y)/2 = 7/2 | (equation 2)
Multiply equation 2 by 2/7:
{2 x+3 y = 9 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{2 x+0 y = 6 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 3 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: | x = 3 and y=1
+129845 2x+3y=9 (1)
x+5y=8 [ multiply this eq. by -2] = -2x - 10y = -16 ..... add this to the first eq.
0 - 7y = -7
-7y = -7 divide both sides by -7 and y = 1
Using (1) to find x
2x + 3(1) = 9
2x + 3 = 9 subtract 3 from both sides
2x = 6 divide both sides by 2
x = 3
So (x , y) = (3, 1)
