((2x)/(4pi))+((1-x))/(2)=0

$$\begin{array}{rlll} \frac{2x}{4\pi}+\frac{1-x}{2}&=&0\\\\ \frac{x}{2\pi}+\frac{1-x}{2}&=&0\\\\ 2\pi \times \left(\frac{x}{2\pi}+\frac{1-x}{2}\right)&=&2\pi\times 0\\\\ x+\pi(1-x)&=&0\\\\ x+\pi-\pi x &=&0\\\\ x(1-\pi )+\pi &=&0\\\\ x(1-\pi )&=&-\pi \\\\ x&=&\frac{-\pi}{(1-\pi )} \\\\ x&=&\frac{\pi}{(\pi-1 )} \\\\ \end{array}$$