2x^5-9x^4+12x^2+10x-3
im stuck with second root, ik that first one is x-1, but lost how to continue :2x^4-7x^3+5x^2-7x+3
\(f(x)=2x^5-9x^4+12x^2-3\)
{nl} im stuck with second root, ik that first one is x-1, but lost how to continue : \(\Large ?\)
2x^4-7x^3+5x^2-7x+3
\(f(x)=2x^4-7x^3+5x^2-7x+3\)
\(x_1=\frac{1}{2}\) \( x_2=3\) !
I suspect your first expression should be: 2x^5-9x^4+12x^3-12x^2+10x-3 as x-1 is a factor of this, but isn't a factor of 2x^5-9x^4+12x^2+10x-3.
asinus's graphical roots suggest that (2x-1) and (x-3) are also factors, so you could try expanding
(2x-1)(x-3)(x-a)(x-b) and comparing the resulting coefficients with 2x^4-7x^3+5x^2-7x+3 to find a and b.
!
