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3,125 = 5^(-10 + 3^x)

 Apr 27, 2016
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Solve for x over the real numbers:
3.125 = 5^(3^x-10)

3.125 = 25/8:
25/8 = 5^(3^x-10)

25/8 = 5^(3^x-10) is equivalent to 5^(3^x-10) = 25/8:
5^(3^x-10) = 25/8

Take the logarithm base 5 of both sides:
3^x-10 = (log(25/8))/(log(5))

Add 10 to both sides:
3^x = 10+(log(25/8))/(log(5))

Take the logarithm base 3 of both sides:
Answer: |  x = (log(10+(log(25/8))/(log(5))))/(log(3))=2.15816660608178

 Apr 27, 2016

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