3[2m-6]=3m-9
You were going pretty good, Complex, until after this step
6m - 18 = 3m - 9 add18 to both sides........subtract 3m from both sides
3m = 9 divide both sides by 3
m = 3
Check this solution in the original problem to see that it "works"
Ok lets see...
\(3[2m-6]=3m-9\)
\([6m-18]=3m-9\)
\(3m-6=-9\)
\(3m = -3\)
\(m=-1\)
Hoped that helped...
-Complex