+214 When written out in a string, your expression is:
\(3(2n–4)– 1 4 n= 3 4 (n+4) n\)
\(6n-12-14n=34n^2+136n\)
\(34n^2+144n+12=0\)
\(17n^2+72n+6=0\)
\(n = {-72 \pm \sqrt{72^2-4\cdot17\cdot6} \over 34} \space \text{(Using the quadratic formula)}\)
\(n=\frac{-72 \pm \sqrt{4776}}{34}\)
\(n=\frac{-72 \pm 2\sqrt{1194}}{34}\)
\(n=\frac{-36 \pm \sqrt{1194}}{17}\)
Which is as simple as we can get it.
