(3-2x)(x+1)=3(2x-3)
3x+3-2x^2-2x=6x-9
-2x^2-7x+12=0
X(1,2)=-(-7)+-√(-7)^2-4*(-2)*12/2(-2)=7+-√145/-4
something is wrong here/where is the mistake?
$$\left(\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}\right){\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)\right) = {\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right) \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\frac{{\mathtt{3}}}{{\mathtt{2}}}}\\
{\mathtt{x}} = -{\mathtt{4}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{1.5}}\\
{\mathtt{x}} = -{\mathtt{4}}\\
\end{array} \right\}$$