3/4-1/3(1/2y-2)=3(y-1/4)
$$\\\frac{3}{4}-\frac{1}{3}(\frac{1}{2}y-2)=3(y-\frac{1}{4})\\\\
\frac{3}{4}-\frac{1}{3}(\frac{y}{2}-2)=3(y-\frac{1}{4})\\\\
\frac{3}{4}-\frac{y}{6}+\frac{2}{3}=3y-\frac{3}{4}\\\\
$Now it will be easier if there were no fractions$\\
$The lowest common multiple of 4,6 and 3 is 12$\\\\
$So multiply both sides by 12 to get rid of all the fractions$\\
12(\frac{3}{4}-\frac{y}{6}+\frac{2}{3})=12(3y-\frac{3}{4})\\\\
\frac{12*3}{4}-\frac{12y}{6}+\frac{12*2}{3}=12*3y-\frac{12*3}{4}\\\\
9-2y+8=36y-9\\\\
17=38y-9\\\\
26=38y\\\\$$
$$\\y=\frac{26}{38}\\\\
y=\frac{13}{19}\\\\$$
3/4-1/3(1/2y-2)=3(y-1/4)
$$\\\frac{3}{4}-\frac{1}{3}(\frac{1}{2}y-2)=3(y-\frac{1}{4})\\\\
\frac{3}{4}-\frac{1}{3}(\frac{y}{2}-2)=3(y-\frac{1}{4})\\\\
\frac{3}{4}-\frac{y}{6}+\frac{2}{3}=3y-\frac{3}{4}\\\\
$Now it will be easier if there were no fractions$\\
$The lowest common multiple of 4,6 and 3 is 12$\\\\
$So multiply both sides by 12 to get rid of all the fractions$\\
12(\frac{3}{4}-\frac{y}{6}+\frac{2}{3})=12(3y-\frac{3}{4})\\\\
\frac{12*3}{4}-\frac{12y}{6}+\frac{12*2}{3}=12*3y-\frac{12*3}{4}\\\\
9-2y+8=36y-9\\\\
17=38y-9\\\\
26=38y\\\\$$
$$\\y=\frac{26}{38}\\\\
y=\frac{13}{19}\\\\$$