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3 4m h (f, Ω)(x) = (Pm k=0(−1)m+k ¡m k ¢ f(x + kh), for [x, x + mh] ⊂ Ω , 0, otherwise

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3 4m h (f, Ω)(x) = (Pm k=0(−1)m+k ¡m k ¢ f(x + kh), for [x, x + mh] ⊂ Ω , 0, otherwise

 
 Jun 8, 2015

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