3/4y-2/3x=12. Find the x and y intercept

3/4y-2/3x=12. Find the x and y intercept

$$\begin{array}{rcl}
\dfrac{3}{4}y-\dfrac{2}{3}x &=& 12 \quad | \quad :12 \\ \\
\dfrac{1}{16}y-\dfrac{1}{18}x &=& 1 \\ \\
\dfrac{y}{16}+\dfrac{x}{-18} &=& 1
\end{array}$$

$$\small{ \text{
y-intercept is 16 and x-intercept is -18
}
}$$

3/4y-2/3x=12

y=((8*x+144)/9)

hope this helped