((3/5)+(pi/7-pi))*((3/5)+(pi/7-pi))=

Simplify the following:
(pi/7-pi+3/5) (pi/7-pi+3/5)

 

Put each term in pi/7-pi+3/5 over the common denominator 35: pi/7-pi+3/5  =  (5 pi)/35-(35 pi)/35+21/35:
(pi/7-pi+3/5) (5 pi)/35-(35 pi)/35+21/35

 

(5 pi)/35-(35 pi)/35+21/35 = (5 pi-35 pi+21)/35:
(pi/7-pi+3/5) (5 pi-35 pi+21)/35

 

Add like terms. 5 pi-35 pi+21  =  21-30 pi:
(pi/7-pi+3/5) (21-30 pi)/35

 

Factor 3 out of 21-30 pi:
((pi/7-pi+3/5)×3 (7-10 pi))/(35)

 

Put each term in pi/7-pi+3/5 over the common denominator 35: pi/7-pi+3/5  =  (5 pi)/35-(35 pi)/35+21/35:
(3 (7-10 pi))/35 (5 pi)/35-(35 pi)/35+21/35

 

(5 pi)/35-(35 pi)/35+21/35 = (5 pi-35 pi+21)/35:
(3 (7-10 pi))/35 (5 pi-35 pi+21)/35

 

Add like terms. 5 pi-35 pi+21  =  21-30 pi:
(3 (7-10 pi))/35 (21-30 pi)/35

 

Factor 3 out of 21-30 pi:
(3 (7-10 pi) 3 (7-10 pi))/(35×35)

 

(3 (7-10 pi)×3 (7-10 pi))/(35×35) = (3×3 (7-10 pi)^2)/(35×35):
(3×3 (7-10 pi)^2)/(35×35)

 

35×35  =  1225:
(3×3 (7-10 pi)^2)/1225

 

3×3  =  9:
Answer: |  (9(7-10 pi)^2)/1225

((3/5)+(pi/7-pi))*((3/5)+(pi/7-pi))=

 

Since  pi/7 - pi  =  pi/7 - 7·pi/7  =  -6·pi/7,

the problem becomes:  ( 3/5 - 6·pi/7 ) · ( 3/5 - 6·pi/7 )

     =       (3/5)·(3/5)  +  (3/5)·( - 6·pi/7 )  +  (3/5)·(  - 6·pi/7 ) + ( - 6·pi/7 )( - 6·pi/7)

     =             9/25  -  18·pi / 35  -  18·pi / 35  +  36·pi² / 49

     =                        9/25  -  36·pi / 35  +  36·pi² / 49