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Algebra 2 help please!!

 Dec 16, 2018
 #1
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1) \(\boxed{xy^5 \sqrt[3]xy}\). You can change the expression directly to \(x^{2\cdot \dfrac{2}{3}}y^{8\cdot \dfrac{2}{3}}\).

 

2) I am not 100% sure about this.

 

3) \(\boxed{\dfrac{x^2-x-6}{2x+3}}\) . Just factor out x^2-9, x^2-3x-10, and 2x^2 - 7x - 15. 

 

 

= (x^4−3x^3−19x^2+27x+90) / 2x^3−x^2−36x−45

= (x+2)(x+3)(x−3)(x−5) / (x+3)(2x+3)(x−5)

= (x^2−x−6) / (2x+3)

 

- PM

 Dec 17, 2018
 #2
avatar+679 
-1

You are welcome! smiley

PartialMathematician  Dec 17, 2018

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