Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
+1
820
2
avatar+29 

Algebra 2 help please!!

 Dec 16, 2018
 #1
avatar+776 
-1

1) xy53xy. You can change the expression directly to x223y823.

 

2) I am not 100% sure about this.

 

3) x2x62x+3 . Just factor out x^2-9, x^2-3x-10, and 2x^2 - 7x - 15. 

 

 

= (x^4−3x^3−19x^2+27x+90) / 2x^3−x^2−36x−45

= (x+2)(x+3)(x−3)(x−5) / (x+3)(2x+3)(x−5)

= (x^2−x−6) / (2x+3)

 

- PM

 Dec 17, 2018
 #2
avatar+776 
-1

You are welcome! smiley

PartialMathematician  Dec 17, 2018

2 Online Users

avatar