1) xy53√xy. You can change the expression directly to x2⋅23y8⋅23.
2) I am not 100% sure about this.
3) x2−x−62x+3 . Just factor out x^2-9, x^2-3x-10, and 2x^2 - 7x - 15.
= (x^4−3x^3−19x^2+27x+90) / 2x^3−x^2−36x−45
= (x+2)(x+3)(x−3)(x−5) / (x+3)(2x+3)(x−5)
= (x^2−x−6) / (2x+3)
- PM