So I was doing an assignment and out of nowhere a question turned up that connfused me a bit.

The question is: Name 3 different ways to calculate the triangles area. The triangle is an perpendicular triangle. (A triangle with one corner that is 90 degrees)


The obvious one is of course B*H/2


The second one I'm thinking of is (a*b*sinC)/2 but I'm unsure if that one works on perpendicular triangles.


The third one I have no clue about. Anyone got any idea? =)

Guest Jun 8, 2017


Let  sides  a,b  be the legs  and c the hypotenuse


Three possibilities


1st  way  =   product of the legs / 2


2nd way =    (1/2) (a)(c)sin B    

Where B is the included angle between sides a and c

Also.....     (1/2) (b) (c) sin A    would work, too


3rd  way.....something known as "Heron's" Formula


The area, A, is given by


√ [  s (s - a) (s - b) ( s - c) ]  


Where  s  = the semi-perimeter =   [ a + b + c ] / 2




cool cool cool

CPhill  Jun 8, 2017

29 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.