So I was doing an assignment and out of nowhere a question turned up that connfused me a bit.
The question is: Name 3 different ways to calculate the triangles area. The triangle is an perpendicular triangle. (A triangle with one corner that is 90 degrees)
The obvious one is of course B*H/2
The second one I'm thinking of is (a*b*sinC)/2 but I'm unsure if that one works on perpendicular triangles.
The third one I have no clue about. Anyone got any idea? =)
Let sides a,b be the legs and c the hypotenuse
1st way = product of the legs / 2
2nd way = (1/2) (a)(c)sin B
Where B is the included angle between sides a and c
Also..... (1/2) (b) (c) sin A would work, too
3rd way.....something known as "Heron's" Formula
The area, A, is given by
√ [ s (s - a) (s - b) ( s - c) ]
Where s = the semi-perimeter = [ a + b + c ] / 2