The first one divisible by 11 is 110
And the last one divisible by 11 is 990
So....the total number =
[ 990 - 110] / 11 + 1 =
80 + 1 =
81
81
Solution:
Step 1 : Find the smallest and largest 3 digit numbers
The smallest 3-digit number = 100
The largest 3 digit number = 999
Step 2 :
Let us find number of numbers divisible by 11 from 1 to 999
999/11 = 90.82
Therefore number of numbers divisible by 11 from 1 to 999 = 90
Step 3 :
Let us find number of numbers divisible by 11 from 1 to 99
99/11 = 9
Therefore number of numbers divisible by 11 from 1 to 99 = 9
Step 4:
Number of numbers divisible by 11 (1 to 999) = 90
Number of numbers divisible by 11 (1 to 99) = 9
Number of numbers divisible by 11 (100 to 999)
= 90 - 9
= 81
Therefore, the number of three-digit numbers (100 to 999) which are divisible by 11 is 81.
Thanks! in this solution I tried to put as many steps as possible so the guest can learn how to do it!