#1**+2 **

The first one divisible by 11 is 110

And the last one divisible by 11 is 990

So....the total number =

[ 990 - 110] / 11 + 1 =

80 + 1 =

81

CPhill May 3, 2020

#2**+3 **

**81**

Solution:

Step 1 : Find the smallest and largest 3 digit numbers

The smallest 3-digit number = 100

The largest 3 digit number = 999

Step 2 :

Let us find number of numbers divisible by 11 from 1 to 999

999/11 = 90.82

Therefore number of numbers divisible by 11 from 1 to 999 = 90

Step 3 :

Let us find number of numbers divisible by 11 from 1 to 99

99/11 = 9

Therefore number of numbers divisible by 11 from 1 to 99 = 9

Step 4:

Number of numbers divisible by 11 (1 to 999) = 90

Number of numbers divisible by 11 (1 to 99) = 9

Number of numbers divisible by 11 (100 to 999)

= 90 - 9

** = 81 **

**Therefore, the number of three-digit numbers (100 to 999) which are divisible by 11 is 81.**

LuckyDucky May 3, 2020

#6**+2 **

Thanks! in this solution I tried to put as many steps as possible so the guest can learn how to do it!

LuckyDucky
May 3, 2020