3 over 2 minus 2 over 3 is equals to?

hi!

your question can be represented as

$${\frac{{\mathtt{3}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}}$$

you can solve this by finding a common denominator, which is done quickly by just multiplying the denominators together, so your new denominator would be 6, or 2*3.

now, because you multiplied 2 by 3 to get 6, your fraction with 2 in the denominator needs the numerator multiplied by 3 as well, making 3/2 into 9/6.

and do the same for 2/3 but multiply both your numerator and denominator by 2, to make 4/6!

so your new equation would be

$${\frac{{\mathtt{9}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{6}}}}$$

and now all you have to do is subtract!

$${\frac{{\mathtt{9}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{6}}}} = {\frac{{\mathtt{5}}}{{\mathtt{6}}}} = {\mathtt{0.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

so your answer as a fraction is 5/6, or as a decimal is 0.83.

hope this helps!

$${\frac{{\mathtt{3}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}} = {\frac{{\mathtt{5}}}{{\mathtt{6}}}} = {\mathtt{0.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$