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In triangle ABC, \(\angle A = 30^\circ\) and \(\angle B = 60^\circ\). Point X is on side \(\overline{AC}\) such that line segment \(\overline{BX}\) bisects \(\angle ABC\). If AB = 12, then find the area of triangle BXA.

 Mar 29, 2020
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Area of triangle BXA is:       A = 12√3 u²    indecision

 Mar 29, 2020

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