32^x-^3=64

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32^x-^3=64

Guest Aug 18, 2015

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Best Answer

+128474

+5

Seems as though I'm having to fill in a lot of "blanks" tonight !!!

I assume we have :

32^{x - 3} = 64 we can write this as:

(2⁵)^{x - 3} = 2⁶ simplify

(2)^{5x - 15} = 2⁶ and since we have equal bases, we can solve for the exponents...so we have...

5x - 15 = 6 add 15 to both sides

5x = 21 divide both sides by 5

x = 21/5

CPhill Aug 18, 2015

1⁺⁰ Answers

+128474

+5

Best Answer

Seems as though I'm having to fill in a lot of "blanks" tonight !!!

I assume we have :

32^{x - 3} = 64 we can write this as:

(2⁵)^{x - 3} = 2⁶ simplify

(2)^{5x - 15} = 2⁶ and since we have equal bases, we can solve for the exponents...so we have...

5x - 15 = 6 add 15 to both sides

5x = 21 divide both sides by 5

x = 21/5

CPhill Aug 18, 2015

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