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# (32k^5)^(2/5)= what in terms of k

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(32k^5)^(2/5)= what in terms of k

Guest May 4, 2017
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$$(32k^5)^{(2/5)}\\ =((2k)^5)^{(2/5)}\\ =(2k)^{(2\cdot5/5)}\\ =(2k)^2\\ =4k^2$$