+11912 So we'd solve this like
as out here we are given the values of x and y so im placing thise values instead of the variables and then sloving this expression!so heer we go
$$36x-8y^2$$
$$=36*3 - 8*(-6)*(-6)$$ (now we will multiply the two parts and then subtract)(out here in the second part which is like 8*9-6)*(-6), first we will multiply the two -6's and then it gives us 36 which we then multiply by 8 )
$$=108-288$$ (now we will simply just subtract them)
$$=-180$$ $$ANSWER$$
I hope uve understood by now but if not then pls be free to ask!
i hope this helps!
+11912 So we'd solve this like
as out here we are given the values of x and y so im placing thise values instead of the variables and then sloving this expression!so heer we go
$$36x-8y^2$$
$$=36*3 - 8*(-6)*(-6)$$ (now we will multiply the two parts and then subtract)(out here in the second part which is like 8*9-6)*(-6), first we will multiply the two -6's and then it gives us 36 which we then multiply by 8 )
$$=108-288$$ (now we will simply just subtract them)
$$=-180$$ $$ANSWER$$
I hope uve understood by now but if not then pls be free to ask!
i hope this helps!
