+0  
 
0
1012
4
avatar

39!C5!  picking 5 numbers from 1-39   please help!

 Mar 12, 2015

Best Answer 

 #4
avatar+26402 
+10

39!C5!  picking 5 numbers from 1-39   please help!

$$\small{\text{
$
\left(\begin{array}{c}
39 \\ 5
\end{array}\right)
$
}}\\\\
\small{\text{
$
\begin{array}{ccc}
&=&\dfrac{39!}{5!\cdot (39-5)! }\\\\
&=&\dfrac{39!}{5!\cdot 34! }\\\\
&=&\dfrac{\not{34!}\cdot 35 \cdot 36 \cdot 37 \cdot 38 \cdot 39}{5!\cdot \not{34!} }\\\\
&=&\dfrac{35 \cdot 36 \cdot 37 \cdot 38 \cdot 39}{2\cdot 3 \cdot 4 \cdot 5}\\\\
&=&\dfrac{35}{5}\cdot \dfrac{36}{4}\cdot 37 \cdot \dfrac{38}{2} \cdot \dfrac{39}{3}\\\\
&=&7\cdot 9 \cdot 37 \cdot 19 \cdot 13\\\\
&=&575757
\end{array}
$
}}$$

 Mar 12, 2015
 #1
avatar
+5

The number of combinations you can make from 39 numbers taken 5 at a time, is 575757.

I don't believe that you meant to use the factorial signs.

 Mar 12, 2015
 #2
avatar+130554 
+5

This is just given by C(39,5)   = 575,757  ways of picking 5 numbers from 39

 

  

 Mar 12, 2015
 #3
avatar+118724 
+5

Yes there are 39C5 different combinations that could be chosen

on the web2 calc you can enter it like this

nCr(39,5)

 Mar 12, 2015
 #4
avatar+26402 
+10
Best Answer

39!C5!  picking 5 numbers from 1-39   please help!

$$\small{\text{
$
\left(\begin{array}{c}
39 \\ 5
\end{array}\right)
$
}}\\\\
\small{\text{
$
\begin{array}{ccc}
&=&\dfrac{39!}{5!\cdot (39-5)! }\\\\
&=&\dfrac{39!}{5!\cdot 34! }\\\\
&=&\dfrac{\not{34!}\cdot 35 \cdot 36 \cdot 37 \cdot 38 \cdot 39}{5!\cdot \not{34!} }\\\\
&=&\dfrac{35 \cdot 36 \cdot 37 \cdot 38 \cdot 39}{2\cdot 3 \cdot 4 \cdot 5}\\\\
&=&\dfrac{35}{5}\cdot \dfrac{36}{4}\cdot 37 \cdot \dfrac{38}{2} \cdot \dfrac{39}{3}\\\\
&=&7\cdot 9 \cdot 37 \cdot 19 \cdot 13\\\\
&=&575757
\end{array}
$
}}$$

heureka Mar 12, 2015

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