A spherical soap bubble lands on a horizontal wet surface and forms a hemisphere of the same volume. Given the radius of the hemisphere is 3 cm, find the radius of the original bubble.
Volume of a cube: 4/3 pi r3
Sphere with 3 cm = 4/3 pi (27) = 36 pi HEMI-sphere is 1/2 of this = 18 pi
Volume of ORIGINAL sphere = 18 pi = 4/3 pi r3
3/4 (18 ) = r3 Solve for the original 'r'
