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Let V = (1,1,2) and let P be the point in the plane \(4x + y - 3z = 1\)  closest to V. 

 

To find P, let Q = (0,1,0), which lies in the plane \(4x + y - 3z = 1\). Find \(\overrightarrow{PV}.\)

 May 1, 2021
 #1
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PV = (-1,8,2).

 May 2, 2021

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