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3h^2+8h+5 how do you work it?

 Jan 15, 2015

Best Answer 

 #1
avatar+808 
+5

Do you mean, solve: 3h2 + 8h + 5 = 0 ?

 

Use the quadratic formula:

 

$$h = \frac{-b +/- sqrt(b^{2}-4ac)}{2a}$$

 

We get:

 

$$h = \frac{-8 +/- sqrt(8*8 - 4*3*5)}{2*3}$$

 

 

$$h= \frac{-8 +/- sqrt(64-60)}{6}$$

 

 

$$h = \frac{-8 +/- 2}{6} => h= \frac{-10}{6} ...v... h=\frac{-6}{6}$$

 

h = - 5/3  v  h = -1 

 

Where v is latin for "vel", indicating inclusive disjunction:

 

A v B means "A or B", or more precise: "either A, or B, or both"

 Jan 16, 2015
 #1
avatar+808 
+5
Best Answer

Do you mean, solve: 3h2 + 8h + 5 = 0 ?

 

Use the quadratic formula:

 

$$h = \frac{-b +/- sqrt(b^{2}-4ac)}{2a}$$

 

We get:

 

$$h = \frac{-8 +/- sqrt(8*8 - 4*3*5)}{2*3}$$

 

 

$$h= \frac{-8 +/- sqrt(64-60)}{6}$$

 

 

$$h = \frac{-8 +/- 2}{6} => h= \frac{-10}{6} ...v... h=\frac{-6}{6}$$

 

h = - 5/3  v  h = -1 

 

Where v is latin for "vel", indicating inclusive disjunction:

 

A v B means "A or B", or more precise: "either A, or B, or both"

Tetration Jan 16, 2015
 #2
avatar+118608 
0

Excellent presentation Tetration   

 Jan 16, 2015

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