Do you mean, solve: 3h2 + 8h + 5 = 0 ?
Use the quadratic formula:
$$h = \frac{-b +/- sqrt(b^{2}-4ac)}{2a}$$
We get:
$$h = \frac{-8 +/- sqrt(8*8 - 4*3*5)}{2*3}$$
$$h= \frac{-8 +/- sqrt(64-60)}{6}$$
$$h = \frac{-8 +/- 2}{6} => h= \frac{-10}{6} ...v... h=\frac{-6}{6}$$
h = - 5/3 v h = -1
Where v is latin for "vel", indicating inclusive disjunction:
A v B means "A or B", or more precise: "either A, or B, or both"
Do you mean, solve: 3h2 + 8h + 5 = 0 ?
Use the quadratic formula:
$$h = \frac{-b +/- sqrt(b^{2}-4ac)}{2a}$$
We get:
$$h = \frac{-8 +/- sqrt(8*8 - 4*3*5)}{2*3}$$
$$h= \frac{-8 +/- sqrt(64-60)}{6}$$
$$h = \frac{-8 +/- 2}{6} => h= \frac{-10}{6} ...v... h=\frac{-6}{6}$$
h = - 5/3 v h = -1
Where v is latin for "vel", indicating inclusive disjunction:
A v B means "A or B", or more precise: "either A, or B, or both"