(3i+1)(1)+(3i+1)(2)+(3i+1)(3)

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(3i+1)(1)+(3i+1)(2)+(3i+1)(3)

Guest Nov 30, 2014

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Best Answer

+130511

+5

(3i+1)(1)+(3i+1)(2)+(3i+1)(3) =

(1 + 2 + 3)(3i + 1)=

6(3i + 1) =

18i + 6

CPhill Nov 30, 2014

1⁺⁰ Answers

+130511

+5

Best Answer

(3i+1)(1)+(3i+1)(2)+(3i+1)(3) =

(1 + 2 + 3)(3i + 1)=

6(3i + 1) =

18i + 6

CPhill Nov 30, 2014

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