3log2(x)-(log2(3)-log2(x+4))

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Guest May 19, 2015

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Best Answer

$\\3log_2(x)-[log_2(3)-log_2(x+4)]\\\\ =3log_2(x)-log_2(3)+log_2(x+4)\\\\ =log_2(x^3)-log_2(3)+log_2(x+4)\\\\ =log_2\;\frac{x^3(x+4)}{3}\\\\$

I am not sure if that is what you wanted :/

Melody May 19, 2015

Melody · Answer 1 · 2015-05-19T01:43:40

$\\3log_2(x)-[log_2(3)-log_2(x+4)]\\\\ =3log_2(x)-log_2(3)+log_2(x+4)\\\\ =log_2(x^3)-log_2(3)+log_2(x+4)\\\\ =log_2\;\frac{x^3(x+4)}{3}\\\\$

I am not sure if that is what you wanted :/