3w^5*7w^5, not to bother you guys... But a little help with this one

OK, rosala.....

Remember that we can multiply in any order that we'd like......so, for instance, 3*4*5 = 5*3*4

So look at this........ 3*w⁵*7*w⁵   is really just the same thing as 3*7 *w⁵ * w⁵

So we have 21*w⁵*w⁵     ....   and remember by a property of exponents (or powers) that aⁿ * aⁿ = aⁿ⁺ⁿ

Therefore, w⁵ * w⁵  =  w⁵⁺⁵ = w¹⁰

And putting this all together, we get ...... 21w¹⁰

Does that make sense??

Are you kool-aids new account......

Oh you mean that one guy who posted that incoherent question? No. A little help?

so well solve it like this :

$$3w^5 * 7w^5$$

for this well use this rule to solve it  $$a^x * b^x$$ $$=(a*b)^x$$

so well do this like this 

= $$(3w * 7w)^5$$    (we multiply both the values )

$$=21w^5$$    ANSWER !   and Pumpkinguy u shouldnt have said like that to KOOL-AID !i hope this helps u !

and who ticked zegroes answer ! i dont think it is correct ! was it u Cphill or melody !

Gotta be careful here, rosala.....

(3w * 7w)⁵  = (21w²)⁵ = (21)⁵ * w¹⁰ = 4,084,101w¹⁰......this is incorrect.....

We have to use this rule here ....   aⁿ * a^m  =  a^m+n

So we have

3w⁵ * 7w⁵  = 3*7*w⁵* w⁵ = 21w¹⁰

And that's the correct answer

CPhill i dont understand it much nicely how u got 21w¹⁰ ! pls can u explain it to me ! 

oh so thats where i made the mistake !i should have been a lil careful but i was careful the thing is that i have never seen this kind of method like solving the problem like this !btw thanks for the explaination , a thumbs up from me for ur lovely explaining answer !

Thumbs up from me for both of you.

thank u very much melody !