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3x^2-22x+140

 May 10, 2016
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Divide both sides by 3:
x^2-(22 x)/3+140/3 = 0

 

Subtract 140/3 from both sides:
x^2-(22 x)/3 = -140/3

 

Add 121/9 to both sides:
x^2-(22 x)/3+121/9 = -299/9

 

Write the left hand side as a square:
(x-11/3)^2 = -299/9

 

Take the square root of both sides:
x-11/3 = (i sqrt(299))/3 or x-11/3 = 1/3 (-i) sqrt(299)

 

Add 11/3 to both sides:
x = 11/3+(i sqrt(299))/3 or x-11/3 = 1/3 (-i) sqrt(299)

 

Add 11/3 to both sides:
Answer: |  x = 11/3+(i sqrt(299))/3     or      x = 11/3-(i sqrt(299))/3

 May 10, 2016

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