-3x^2-24x-48 use the quadratic formula to solve this. Whats the deal with the imaginary numbers? I dont understand.
Go online to this calculator and enter your numbers in it:
http://www.mathwarehouse.com/quadratic/quadratic-formula-calculator.php
+118723 -3x^2-24x-48 use the quadratic formula to solve this. Whats the deal with the imaginary numbers? I dont understand.
Firstly there is nothing to solve because there is no equal sign.
You could solve
-3x^2-24x-48=0
I would divide by -3 before I used the quadrativ formula.
You do not need to but the numbers will be easier to work with
\(-3x^2-24x-48=0\\ x^2+8x+16=0\\ (x+4)(x+4)=0\\ x=-4\\~\\ \)
There is a double root at x=-4 This means that the vertex of the parabola will be where x=-4
Now I will use the quadratic formula as you asked
\(-3x^2-24x-48\\ a=-3,\qquad b=-24, \qquad c=-48\\ x =\frac {-b \pm \sqrt{b^2-4ac} } {2a}\\ x =\frac {--24 \pm \sqrt{(-24)^2-4*-3*-48} } {2*-3}\\ x =\frac {--24 \pm \sqrt{576-576 }} {-6}\\ x =\frac {+24 \pm 0} {-6}\\ x =\frac {+24 } {-6}\\ x=-4\)
