3x^4 -5x^2+x-3 x=2 ?
So x=2?
$${\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{4}}}{\mathtt{\,-\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{3}} = {\mathtt{27}}$$