+3453 The order of operations says we have to do multiplication before addition. A good way to remember the order of operations is to remember "PEMDAS."
So you do parenthesis first, then exponets, then multiplication & division, (whichever comes first) then addition & subtraction (whichever comes first)
Here's how you'd work it out.
+3453 The order of operations says we have to do multiplication before addition. A good way to remember the order of operations is to remember "PEMDAS."
So you do parenthesis first, then exponets, then multiplication & division, (whichever comes first) then addition & subtraction (whichever comes first)
Here's how you'd work it out.
+128474 Very nice, ND.....you missed your calling.....you should have been a graphic artist!!
+118609 Yes Ninja, it is easier to take things in if they are well presented.
This is beautiful. 
Since you are only 14 I don't think that you have missed anything just yet! 
+8261 $${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{60}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{2}}$$
You have to use the order of operations to do this problem.
An easy way to remember it is PEMDAS, or PEDMAS.
PEDMAS = Parentheses, Exponents, Division, Multiplication, Addition, & Subtraction.
PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, & Subtraction.
Now let's multiply the question one by one.
$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\mathtt{180}}$$
$${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{9}} = {\mathtt{45}}$$
$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{4}}$$
Now that we got everything, let's add it.
$${\mathtt{180}}{\mathtt{\,\small\textbf+\,}}{\mathtt{45}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}} = {\mathtt{225}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}} = {\mathtt{229}}$$
So, our final answer is $${\mathtt{229}}$$.
It is simple as that.
