3y^1/3 -2 = 4

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3y^1/3 -2=4

Guest Jun 19, 2015

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I like the way that you have done this anon, I just want to have a play with it :)

$$\\3y^{1/3} -2=4\\\\
3y^{1/3} =6\\\\
y^{1/3} =2\\\\
(y^{1/3})^3 =2^3\\\\
y=8$$

Mmm so you didn't really need to use logs but both our answers are good :)

Melody Jun 19, 2015

Melody · Answer 1 · 2015-06-19T08:55:45

I like the way that you have done this anon, I just want to have a play with it :)

$$\\3y^{1/3} -2=4\\\\
3y^{1/3} =6\\\\
y^{1/3} =2\\\\
(y^{1/3})^3 =2^3\\\\
y=8$$

Mmm so you didn't really need to use logs but both our answers are good :)

Guest · Answer 2 · 2015-06-19T01:49:16

3*y^(1/3) - 2 = 4

3*y^(1/3) = 4 + 2 = 6

y^(1/3) = 6 / 3 = 2

1/3 * Log(y) = Log(2)

Log(y) = Log(2) / (1/3) = Log(2) * 3

Log(y) = Log(2^3)

y = 2^3 = 8