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(3y^2-5x^2+4)-(2x-8+4y^2)

 Jun 23, 2014

Best Answer 

 #1
avatar+130511 
+5

(3y^2-5x^2+4)-(2x-8+4y^2)

Distributing the negative across the terms in the second set of parethesis, we have:

3y^2 - 5x^2 + 4 -  2x + 8 - 4y^2   Combine like terms

3y^2 - 4y^2 - 5x^2 - 2x + 4 + 8  =

- y^2 - 5x^2 - 2x + 12

 

 Jun 23, 2014
 #1
avatar+130511 
+5
Best Answer

(3y^2-5x^2+4)-(2x-8+4y^2)

Distributing the negative across the terms in the second set of parethesis, we have:

3y^2 - 5x^2 + 4 -  2x + 8 - 4y^2   Combine like terms

3y^2 - 4y^2 - 5x^2 - 2x + 4 + 8  =

- y^2 - 5x^2 - 2x + 12

 

CPhill Jun 23, 2014

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