+0  
 
+3
525
2
avatar

3y-5x=-13 

Guest Aug 3, 2014

Best Answer 

 #2
avatar+92805 
+13

Great answer Ninja,

Grreat use of LaTex too!  (I answered your latex question for you as well)

I'm going to do it a different way (and I will practice some LaTex while I am at it)

3y-5x=-13

 $$\\If\; x=0\;\; then \;\;3y=-13 \;\;so \;\;y=\frac{-13}{3}=-4\frac{1}{3}\;\;(0,-4\frac{1}{3})\\\\
If\; y=0\;\; then \;\;-5x=-13 \;\;so \;\;x=\frac{13}{5}=2\frac{3}{5}\;\;\;(2\frac{3}{5},0)\\\\
\begin{array}{|c|c|c|}\hline
$x$&0&2\frac{3}{5}\\\hline
$y$&-4\frac{1}{3}&0\\\hline
\end{array}\\$$

 

 

 

FOR PEOPLE LEARNING LATEX

This is the code that I have used.

\\If\; x=0\;\; then \;\;3y=-13 \;\;so \;\;y=\frac{-13}{3}=-4\frac{1}{3}\;\;(0,-4\frac{1}{3})\\\\

If\; y=0\;\; then \;\;-5x=-13 \;\;so \;\;x=\frac{13}{5}=2\frac{3}{5}\;\;\;(2\frac{3}{5},0)\\\\

\begin{array}{|c|c|c|}\hline

$x$&0&2\frac{3}{5}\\\hline

$y$&-4\frac{1}{3}&0\\\hline

\end{array}\\

I drew the picture with GeoGebra

Melody  Aug 4, 2014
 #1
avatar+3450 
+13

Are you wondering how you graph this?

To do this, you have to switch it to the slope intercept form.

The slope intercept form is y = mx + b, where m = slope and b = y intercept.

Let's work this out.

$$\begin{array}{rll}
3y -5x &=&-13\\
y- 5/3x &=& -13/3\\
y &=& 5/3x - 13/3\\
y &=& 5/3x -4 \frac{1}{3}
\end{array}$$

We can plot the point (0, -4 1/3) now, because the -4 1/3 tells us the y intercept.

Then, from that point, we can go up 5 and over 3 to the right. We do this because 5/3 tells us our slope, and it is written as up/over. I know to go 3 to the right because this is a positive slope.

If you had something like y = -5/3x + 2, you would go over 3 to the left, because that would be a negative slope.

Anyway, we go up 5 and over 3 to the right, then plot that point (put a dot there.) Now we have two points so we grab a ruler and draw a line through those two points. That's our graphed line!

Here's what this one will look like:

NinjaDevo  Aug 4, 2014
 #2
avatar+92805 
+13
Best Answer

Great answer Ninja,

Grreat use of LaTex too!  (I answered your latex question for you as well)

I'm going to do it a different way (and I will practice some LaTex while I am at it)

3y-5x=-13

 $$\\If\; x=0\;\; then \;\;3y=-13 \;\;so \;\;y=\frac{-13}{3}=-4\frac{1}{3}\;\;(0,-4\frac{1}{3})\\\\
If\; y=0\;\; then \;\;-5x=-13 \;\;so \;\;x=\frac{13}{5}=2\frac{3}{5}\;\;\;(2\frac{3}{5},0)\\\\
\begin{array}{|c|c|c|}\hline
$x$&0&2\frac{3}{5}\\\hline
$y$&-4\frac{1}{3}&0\\\hline
\end{array}\\$$

 

 

 

FOR PEOPLE LEARNING LATEX

This is the code that I have used.

\\If\; x=0\;\; then \;\;3y=-13 \;\;so \;\;y=\frac{-13}{3}=-4\frac{1}{3}\;\;(0,-4\frac{1}{3})\\\\

If\; y=0\;\; then \;\;-5x=-13 \;\;so \;\;x=\frac{13}{5}=2\frac{3}{5}\;\;\;(2\frac{3}{5},0)\\\\

\begin{array}{|c|c|c|}\hline

$x$&0&2\frac{3}{5}\\\hline

$y$&-4\frac{1}{3}&0\\\hline

\end{array}\\

I drew the picture with GeoGebra

Melody  Aug 4, 2014

5 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.