What is the area of triangle BCD to the nearest tenth of a square centimeter? Use special right triangles to help find the height
This is a 30-60-90 right triangle
The side opposite the 30 degree angle = 5 = the base
The side opposite the 60 degree = sqrt(3) * the side opposite the 30 degree angle = 5*sqrt (3)....this is the height
So....tha area is
(1/2) base * height =
(1/2) 5 * 5sqrt(3) =
( sqrt (3) / 2) * 25 cm^2 ≈ 21.65 cm^2