(4/3) y-1 =3/4 (4/3) (it's an inverse function problem)

\(\frac{4}{3} y-1 =\frac{3}{4}\\ \frac{4}{3} y-1+1 =\frac{3}{4}+1\\ \frac{4}{3} y=\frac{7}{4}\\ \frac{4}{3}*\frac{3}{4} y=\frac{7}{4}*\frac{3}{4}\\ y=\frac{21}{16}\\ y=1\frac{5}{16}\\\)

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