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(-2, -4) , (0, 0), (4, a) and (b,18) is on a perpendicular choose the sum of A and B

 Jul 11, 2015

Best Answer 

 #2
avatar+128399 
+5

I'm going to take a guess here........I think (-2, -4) and (0, 0) are on one line and (4, a) and (b, 18) are on a perpendicular line......so....the slope of the first line is

 

[-4 -0] / [-2 -0] =  -4/-2 = 2

 

And for the second line, the slope would be  -1/2  ....so we have......

 

[18 - a] / [ b - 4]  = -1/2    ...... or.....   

 

2[18 - a]  = 4 - b

 

36 -  2a = 4 - b

 

b = 2a - 32     

 

Then, we can "choose" any sum we want.....for instance, letting a = 16 means that b  =  0

 

And their sum is just 16 

 

[I have no idea if this is the correct interpretation, or not  !!! ]

 

 

  

 Jul 11, 2015
 #1
avatar+118608 
+5

I have no idea what you re talking about -

 

Hey Chris, do you understand this one?

 Jul 11, 2015
 #2
avatar+128399 
+5
Best Answer

I'm going to take a guess here........I think (-2, -4) and (0, 0) are on one line and (4, a) and (b, 18) are on a perpendicular line......so....the slope of the first line is

 

[-4 -0] / [-2 -0] =  -4/-2 = 2

 

And for the second line, the slope would be  -1/2  ....so we have......

 

[18 - a] / [ b - 4]  = -1/2    ...... or.....   

 

2[18 - a]  = 4 - b

 

36 -  2a = 4 - b

 

b = 2a - 32     

 

Then, we can "choose" any sum we want.....for instance, letting a = 16 means that b  =  0

 

And their sum is just 16 

 

[I have no idea if this is the correct interpretation, or not  !!! ]

 

 

  

CPhill Jul 11, 2015
 #3
avatar+118608 
0

Mmm  maybe :))

 Jul 11, 2015

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