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(4-a)x(asquare+7a-18)=

 Nov 5, 2015
 #1
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4-a)x(asquare+7a-18)=

(4-a) X (a^2 + 7a - 18)=

 

Solve for a over the real numbers:
-((a-4) (a^2+7 a-18)) = 0

Multiply both sides by -1:
(a-4) (a^2+7 a-18) = 0

Split into two equations:
a-4 = 0 or a^2+7 a-18 = 0

Add 4 to both sides:
a = 4 or a^2+7 a-18 = 0

The left hand side factors into a product with two terms:
a = 4 or (a-2) (a+9) = 0

Split into two equations:
a = 4 or a-2 = 0 or a+9 = 0

Add 2 to both sides:
a = 4 or a = 2 or a+9 = 0

Subtract 9 from both sides:
Answer: | 
| a = 4 or a = 2 or a = -9

 Nov 5, 2015

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