1.)
8x + 50 = 130
x = 10
2.)
2x + 3x + 3x = 180
x = 45/2
y = 2x
y=2(45/2)
y=45
1 The two labelled angleas are the same measure so 130 = 8x +50 solve for x
2 Triangles angles add to 180 so 180 = 2x + 3x + 2x solve for x angle s = 2x
3 I assume 5x is actually 5y
angles add to 180 degrees so 2y+20 + 5y + 40 = 180 solve for y
4 AC and AB are same length so 2x+23 = 4x+1 solve for x and substitute into 3x-8 to find BC
OK....I see that now
5x = 40 degrees (since the opposite sides are =)
180 degrees in a triangle so 40 + 40 + 2y+20 = 180 solve for y = 40