4(lnz+ln(z+5))-2ln(z-5)
$$\\4(lnz+ln(z+5))-2ln(z-5)\\ =2[2(lnz+ln(z+5))-ln(z-5)]\\ =2[2lnz+2ln(z+5)-ln(z-5)]\\ =2[lnz^2+ln(z+5)^2-ln(z-5)]\\ =2[ln(z^2\times (z+5)^2 \div (z-5))]\\\\ =2\;ln\;\frac{z^2 (z+5)^2}{z-5}\\\\$$