4 sec (pi/6)+5 cot(pi/4) how do i solve this

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4 sec (pi/6)+5 cot(pi/4) how do i solve this

Guest Oct 6, 2014

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Best Answer

+128707

+5

4 sec (pi/6)+5 cot(pi/4)

sec(pi/6) = 1/cos(pi/6) = (1)/(√3/2) = 2/√3

cot(pi/4) = 1/tan(pi/4) = 1/1 = 1

So we have

4(2/√3) + 5*1 =

8/√3 + 5 =

8√3/3 + 15/3 =

[8√3 + 15] / 3

CPhill Oct 6, 2014

1⁺⁰ Answers

+128707

+5

Best Answer

4 sec (pi/6)+5 cot(pi/4)

sec(pi/6) = 1/cos(pi/6) = (1)/(√3/2) = 2/√3

cot(pi/4) = 1/tan(pi/4) = 1/1 = 1

So we have

4(2/√3) + 5*1 =

8/√3 + 5 =

8√3/3 + 15/3 =

[8√3 + 15] / 3

CPhill Oct 6, 2014

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