4^x+3=10^2-x
$$4^x+3=10^2-x \qquad4^x=100-3-x \qquad 4^x=97-x$$
$$x \approx 3.275179625$$
$$\\\small{\text{$ 4^{x+3}=10^{2-x} \quad 4^x*4^3=10^2*10^{-x} \quad (4*10)^x=\frac{5^2}{4^2} \quad 40^x = 1.25^2 \; | \;\ln $ }}\\\small{\text{$ x\ln{(40)}= 2*\ln{(1.25)} \quad x = 2*\frac{\ln{(1.25)}}{\ln{(40)}} \quad x=0.12098175291$}}$$