(4+x)(3)+(x)(41)=(8)(x-2)

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Guest Sep 23, 2014

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Best Answer

(4+x)(3)+(x)(41)=(8)(x-2) simplify

12 + 3x + 41x = 8x - 16 combine like term

12 + 44x = 8x - 16 subtract 8x from both sides and subtract 12 from both sides

36x = -28 divide both sides by 3

x = -28/36 = -7/9

CPhill Sep 23, 2014

CPhill · Answer 1 · 2014-09-23T09:49:16

(4+x)(3)+(x)(41)=(8)(x-2) simplify

12 + 3x + 41x = 8x - 16 combine like term

12 + 44x = 8x - 16 subtract 8x from both sides and subtract 12 from both sides

36x = -28 divide both sides by 3

x = -28/36 = -7/9

Landry · Answer 2 · 2014-09-23T09:35:40

X is equal to 4/45