Guys how to make 41 with digits 2 0 2 3
im stuck pls helppp
It‘s
2
Σ n^2
n=3+0!
basically the starting n^2 is 3+0! = 4
so 4^2
and the 2 at the top means how many times
so 4^2+5^2
=16+25
=41
I'm sorry but I do not understand what you have done here.
its the answer...
I suspect this is what was meant:
Thanks Alan,
\(\displaystyle \frac{2^{3}}{.2}+0!\)
Very nice Tiggsy.
It is good to see you here :)
