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[48+(2-1)/7+[50+(2-2)]/2-square root of 4+50

 Jul 15, 2014
 #1
avatar+3502 
0

Well doing all of that in the calculator minus the brackets=[ you get rounded up 98.14 and the square root of 50+4=54 the square root itself looks like this     54=(9*6)=3  6

 Jul 15, 2014
 #2
avatar+118723 
0

$$\frac {48+\frac{(2-1)}{7}+50+(2-2)}{2}-\sqrt{4}+50\\\\
=\frac {48+\frac{1}{7}+50+(0)}{2}-2+50\\\\
=\frac {48+\frac{1}{7}+50}{2}-2+50\\\\
=\frac {98+\frac{1}{7}}{2}-2+50\\\\$$

 

$${\frac{\left({\mathtt{98}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}\right)}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}} = {\frac{{\mathtt{1\,359}}}{{\mathtt{14}}}} = {\mathtt{97.071\: \!428\: \!571\: \!428\: \!571\: \!4}}$$

 

Umm different answer from zegroes - lets try the site calc.

$$\left({\mathtt{48}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{7}}}}{\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{50}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{2}}\right)\right)}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{4}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}\right) = {\frac{{\mathtt{848}}}{{\mathtt{7}}}} = {\mathtt{121.142\: \!857\: \!142\: \!857\: \!142\: \!9}}$$

 

ok lots of different answers happening here.  One of the reasons is that there is a bracket missing in the questions and it keeps getting interpreted differently.

Fix up the bracket and we will fix up our anwers.    

 Jul 15, 2014

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