48/4^2+3over5
$${\frac{{\mathtt{48}}}{{{\mathtt{4}}}^{{\mathtt{2}}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{5}}}} = {\frac{{\mathtt{18}}}{{\mathtt{5}}}} = {\mathtt{3.6}}$$