48 g out of 60 g ?%
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\(60g:100\%=48g:x\\x\cdot 60g=48g\cdot 100\%\\ x= \dfrac{48g\cdot 100\%}{60g}\\ \color{blue}x=80\% \)
\(48 g\ of\ 60 g\ is\ 80\% .\)
or so: \(\dfrac{48g}{60g}=\dfrac{4}{5}=0.8=\color{blue}80\%\)
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