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4x^2-16x+7        

---------------          >3

x^2-4x+4

 Dec 20, 2014

Best Answer 

 #1
avatar+23246 
+5

(4x² - 16x + 7) / (x² - 4x + 4)  >  3

Multiply both sides by  x² - 4x + 4:

4x² - 16x + 7  >  3(x² - 4x + 4)

4x² - 16x + 7  >  3x² - 12x + 12

Subtract  3x² - 6x + 12 from both sides:

x² - 4x - 5  >  0

(x - 5)(x + 1) > 0

Either  both x - 5 and x + 1 are positive   or  both x - 5 and x + 1 are negative.

If  x - 5 > 0  and  x + 1 > 0   --->   x > 5  and  x > -1   --->   x > 5

If  x - 5 < 0  and  x + 1 < 0   --->   x < 5  and  x < -1   --->   x < -1

Answer:  x < -1  or  x > 5

 Dec 20, 2014
 #1
avatar+23246 
+5
Best Answer

(4x² - 16x + 7) / (x² - 4x + 4)  >  3

Multiply both sides by  x² - 4x + 4:

4x² - 16x + 7  >  3(x² - 4x + 4)

4x² - 16x + 7  >  3x² - 12x + 12

Subtract  3x² - 6x + 12 from both sides:

x² - 4x - 5  >  0

(x - 5)(x + 1) > 0

Either  both x - 5 and x + 1 are positive   or  both x - 5 and x + 1 are negative.

If  x - 5 > 0  and  x + 1 > 0   --->   x > 5  and  x > -1   --->   x > 5

If  x - 5 < 0  and  x + 1 < 0   --->   x < 5  and  x < -1   --->   x < -1

Answer:  x < -1  or  x > 5

geno3141 Dec 20, 2014

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