(4x^2-2x/x^2+5x+4)/(2x/x^2+2x+1) how do i do this

$$(4x^2-2x/x^2+5x+4)/(2x/x^2+2x+1)$$

I assume that you really mean

$$\\((4x^2-2x)/(x^2+5x+4))/((2x)/(x^2+2x+1) )\\\\ =\frac{4x^2-2x}{x^2+5x+4}\div\frac{2x}{x^2+2x+1}\\\\ =\frac{4x^2-2x}{x^2+5x+4}\times\frac{x^2+2x+1}{2x}\\\\ =\frac{x(x-2)}{(x+4)(x+1)}\times\frac{(x+1)(x+1)}{2x}\\\\ =\frac{(x-2)}{(x+4)}\times\frac{(x+1)}{2}\\\\ =\frac{(x-2)(x+1)}{2(x+4)}\\\\ =\frac{x^2-x-2}{2x+8}\\\\$$