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4x^2+56x+196=0

 

solve for x 

 Sep 28, 2015
 #1
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+5

4x^2+56x+196=0

 

x= -7, here is step by step solution:

 

Solve for x over the real numbers:
4 x^2+56 x+196 = 0
Write the quadratic equation in standard form.
Divide both sides by 4:
x^2+14 x+49 = 0
Factor the left hand side.
Write the left hand side as a square:
(x+7)^2 = 0
Eliminate the exponent on the left hand side.
Take the square root of both sides:
x+7 = 0
Solve for x.
Subtract 7 from both sides:
Answer: | 
| x = -7

 Sep 29, 2015

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