(5!/0!(5-0)) .3^2 .7^3

(5!/0!*(5-0))*3²*7³           correct ??

=120/1 *5*9*343 =

= $${\mathtt{120}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{343}} = {\mathtt{1\,852\,200}}$$

did you intend that to be

x 3^2 x 7^3

or

x 0.3^2  x 0.7^3               ??